How to Use The Shell Method To Calculate Volume (Calculus 2 Lesson 4)
In this video we look at how to use definite integrals to calculate the volume of solids of revolution using the shell method. We discuss how to use the method when a region is revolved around the x-axis to form a solid, when a region is revolved around the y-axis to form a solid, and when the region is revolved around a line other than the x- or y-axis to form a solid. Additionally, we compare the shell method to the disk and washer methods and when each method is preferable.
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This series is designed to help students understand the concepts of Calculus 2 at a grounded level. No long, boring, and unnecessary explanations, just what you need to know at a reasonable and digestible pace, with the goal of each video being shorter than the average school lecture!
Calculus 2 requires a solid understanding of calculus 1, precalculus, and algebra concepts and techniques. This includes limits, differentiation, basic integration, factoring, equation manipulation, trigonometric functions, logarithms, graphing, and much more. If you are not familiar with these prerequisite topics, be sure to learn them first!
Video Chapters:
0:00 The Shell Method (y-axis)
6:15 The Shell Method (x-axis)
9:14 Summary of Formulas
10:46 How to Adjust Height When Between Two Curves
12:34 Example 1 - y=x^3, x=1, y=0 around y-axis
17:35 Example 2 - y=x^2, x=1, y=0 around x-axis
25:02 How to Adjust Radius When Revolving Around Other Lines
28:50 Example 3 Part 1 - y=x, y=sqrt(x) around y=1
32:41 Example 3 Part 2 - y=x, y=sqrt(x) around y=-1
34:55 Example 3 Part 3 - y=x, y=sqrt(x) around x=1
37:23 Example 3 Part 4 - y=x, y=sqrt(x) around x=-1
39:19 Comparison to Disk/Washer Method
41:02 Example 4 - When Shell Method is Preferable
46:30 Outro
📝 Examples Video:
https://youtu.be/PDVzPFFHuF4
⏩ Next Lesson:
https://youtu.be/hnA9P2grADA
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Corrections:
46:15 I made a mistake here with the second integral. Since we are revolving around the y-axis, both integrals should be entirely in terms of y for the disk/washer method. To fix this mistake, solve for x in the function y=x^2+1 to get x=√(y-1) as the inner radius and substitute that in for where I put x^2+1. And then of course, there should be a dy instead of dx at the end of the integral.
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