Equation of Parabola Part 1 [Class 12 Basic Mathematics Conic Section] Solution

Part 1. Introduction and Derivation of Equation of Parabola in standard form y= 4ax https://youtu.be/e5d72OfGiEo Part 2. Finding the equation of parabola at given point: (a) Vertex (0,0), Focus (4,0) (b) Vertex (-1, 3), Focus (5,3) (c) Vertex (2, 3), Focus (2, 5) https://youtu.be/pt8mxMLO4kU Part 3. Finding the equation of parabola at given conditions a. Vertex at (-5, -3), and end of latus rectum (-1, 5), and (-1, -11) b. focal width 16, axis parallel to x- axis, passing through (3,7) and (3,-1) https://youtu.be/hMxusgkzMgQ Part 4. Finding coordinates of the vertex, the focus, equation of directrix, length of latus rectum (a) y^2= 16x (b) y^2 =6y-12x+45 https://youtu.be/4cWxgpH-8Cg Part 5. A double ordinate of the parabola y^2 = 2ax is of length 4a. Prove that the lines joining the vertex to its ends are at right angles. https://youtu.be/zU7aKjCAv04 Part 6. Find the locus of middle points of the chords of the parabola y = 4ax passing through vertex. Prove that it is a parabola. Find its latus rectum. https://youtu.be/8_fLDoh9ytw Basic Math Class 12 Conic Section Parabola Equation of parabola Unit 4 Conic Section Exercise 4.1 Equation of Parabola +2 NEB Basic Math Class 12 Solution For More: Kshitiz Subedi Contact: [email protected] Facebook https://facebook.com/Subediksz Contact: 977-9849740419 EDU GLOBAL FOUNDATION 01-5218180