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Hi Everyone, this is the 85th video of our Playlist "Leetcode Easy".
Now we will be solving a good but easy Problem - Build Array from Permutation | Follow Up Qn | Detailed Explanation | Leetcode 1920 | codestorywithMIK
I will explain it in full detail so that it becomes easy to understand. We will find the reason behind everything so that we understand why we did what we did.
And we will do a complete dry run.
Problem Name : Build Array from Permutation | Follow Up Qn | Detailed Explanation | Leetcode 1920 | codestorywithMIK
Company Tags : will update later
Code Github(C++ & JAVA) - will update later tonight
Leetcode Link : https://leetcode.com/problems/build-array-from-permutation
My DP Concepts Playlist :
https://youtu.be/7eLMOE1jnls
My Graph Concepts Playlist :
https://youtu.be/5JGiZnr6B5w
My Segment Tree Concepts Playlist :
https://www.youtube.com/watch?v=k99r1A7krcY&list=PLpIkg8OmuX-K1qUIQToCllUO0UIKXt8dB
My Recursion Concepts Playlist :
https://www.youtube.com/watch?v=pfb1Zduesi8&list=PLpIkg8OmuX-IBcXsfITH5ql0Lqci1MYPM
Trie Playlist -
https://www.youtube.com/watch?v=DMP2bqW6URA&list=PLpIkg8OmuX-I99uuP2BZOz4mI_lms4gVG
Difference Array Technique: Concepts & Qns :
https://www.youtube.com/watch?v=ZHNVmtm08WY&list=PLpIkg8OmuX-Kqkb8DqDe_4-Tiav6ilS_L
My GitHub Repo for interview preparation : https://github.com/MAZHARMIK/Interview_DS_Algo
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Video Summary :
The problem requires constructing an array such that ans[i] = nums[nums[i]].
Instead of using extra space, the solution encodes both old and new values into each element using the formula:
nums[i] = nums[i] + n * (nums[nums[i]] % n), where % n ensures correct value extraction.
In the second pass, nums[i] is divided by n to retrieve only the newly encoded value, achieving an in-place transformation.
This approach uses mathematical encoding to meet the O(1) space constraint.
✨ Timelines✨
00:00 - Introduction
0:19 - Motivation
0:49 - Problem Explanation
3:53 - Simple Approach
4:41 - Follow Up Qn
8:20 - Detailed with example
21:50 - Story To Code
24:19 - Coding it up
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